PSLEIn the figure, DEFG is a parallelogram. DBG and BFC are straight lines. ∠CFG = 152°, ∠DGF = 48° and ∠DFB = 20°.
- Find ∠EFC.
- Find ∠EDF.
(a)
∠EFG
= 180° - 48°
= 132° (Interior angles)
∠EFC
= 360° - 152° - 132°
= 76° (Angles at a point)
(b)
∠GFB
= 180° - 152°
= 28°(Angles on a straight line)
∠EDF
= ∠DFG
= 28° + 20°
= 48° (Alternate angles)
Answer(s): (a) 76°; (b) 48°