PSLEIn the figure, EFGH is a parallelogram. ECH and CGD are straight lines. ∠DGH = 151°, ∠EHG = 48° and ∠EGC = 17°.
- Find ∠FGD.
- Find ∠FEG.
(a)
∠FGH
= 180° - 48°
= 132° (Interior angles)
∠FGD
= 360° - 151° - 132°
= 77° (Angles at a point)
(b)
∠HGC
= 180° - 151°
= 29°(Angles on a straight line)
∠FEG
= ∠EGH
= 29° + 17°
= 46° (Alternate angles)
Answer(s): (a) 77°; (b) 46°