PSLEIn the figure, ZABC is a parallelogram. ZXC and XBY are straight lines. ∠YBC = 148°, ∠ZCB = 45° and ∠ZBX = 23°.
- Find ∠ABY.
- Find ∠AZB.
(a)
∠ABC
= 180° - 45°
= 135° (Interior angles)
∠ABY
= 360° - 148° - 135°
= 77° (Angles at a point)
(b)
∠CBX
= 180° - 148°
= 32°(Angles on a straight line)
∠AZB
= ∠ZBC
= 32° + 23°
= 55° (Alternate angles)
Answer(s): (a) 77°; (b) 55°