PSLEIn the figure, FGHJ is a parallelogram. FDJ and DHE are straight lines. ∠EHJ = 150°, ∠FJH = 42° and ∠FHD = 22°.
- Find ∠GHE.
- Find ∠GFH.
(a)
∠GHJ
= 180° - 42°
= 138° (Interior angles)
∠GHE
= 360° - 150° - 138°
= 72° (Angles at a point)
(b)
∠JHD
= 180° - 150°
= 30°(Angles on a straight line)
∠GFH
= ∠FHJ
= 30° + 22°
= 52° (Alternate angles)
Answer(s): (a) 72°; (b) 52°