PSLEIn the figure, BCDE is a parallelogram. BZE and ZDA are straight lines. ∠ADE = 152°, ∠BED = 48° and ∠BDZ = 19°.
- Find ∠CDA.
- Find ∠CBD.
(a)
∠CDE
= 180° - 48°
= 132° (Interior angles)
∠CDA
= 360° - 152° - 132°
= 76° (Angles at a point)
(b)
∠EDZ
= 180° - 152°
= 28°(Angles on a straight line)
∠CBD
= ∠BDE
= 28° + 19°
= 47° (Alternate angles)
Answer(s): (a) 76°; (b) 47°