PSLEIn the figure, EFGH is a parallelogram. ECH and CGD are straight lines. ∠DGH = 153°, ∠EHG = 48° and ∠EGC = 18°.
- Find ∠FGD.
- Find ∠FEG.
(a)
∠FGH
= 180° - 48°
= 132° (Interior angles)
∠FGD
= 360° - 153° - 132°
= 75° (Angles at a point)
(b)
∠HGC
= 180° - 153°
= 27°(Angles on a straight line)
∠FEG
= ∠EGH
= 27° + 18°
= 45° (Alternate angles)
Answer(s): (a) 75°; (b) 45°