PSLEIn the figure, DEFG is a parallelogram. DBG and BFC are straight lines. ∠CFG = 153°, ∠DGF = 47° and ∠DFB = 19°.
- Find ∠EFC.
- Find ∠EDF.
(a)
∠EFG
= 180° - 47°
= 133° (Interior angles)
∠EFC
= 360° - 153° - 133°
= 74° (Angles at a point)
(b)
∠GFB
= 180° - 153°
= 27°(Angles on a straight line)
∠EDF
= ∠DFG
= 27° + 19°
= 46° (Alternate angles)
Answer(s): (a) 74°; (b) 46°