PSLEIn the figure, JKLM is a parallelogram. JGM and GLH are straight lines. ∠HLM = 150°, ∠JML = 48° and ∠JLG = 18°.
- Find ∠KLH.
- Find ∠KJL.
(a)
∠KLM
= 180° - 48°
= 132° (Interior angles)
∠KLH
= 360° - 150° - 132°
= 78° (Angles at a point)
(b)
∠MLG
= 180° - 150°
= 30°(Angles on a straight line)
∠KJL
= ∠JLM
= 30° + 18°
= 48° (Alternate angles)
Answer(s): (a) 78°; (b) 48°