PSLEIn the figure, CDEF is a parallelogram. CAF and AEB are straight lines. ∠BEF = 152°, ∠CFE = 42° and ∠CEA = 22°.
- Find ∠DEB.
- Find ∠DCE.
(a)
∠DEF
= 180° - 42°
= 138° (Interior angles)
∠DEB
= 360° - 152° - 138°
= 70° (Angles at a point)
(b)
∠FEA
= 180° - 152°
= 28°(Angles on a straight line)
∠DCE
= ∠CEF
= 28° + 22°
= 50° (Alternate angles)
Answer(s): (a) 70°; (b) 50°