PSLEIn the figure, KLMN is a parallelogram. KHN and HMJ are straight lines. ∠JMN = 152°, ∠KNM = 48° and ∠KMH = 20°.
- Find ∠LMJ.
- Find ∠LKM.
(a)
∠LMN
= 180° - 48°
= 132° (Interior angles)
∠LMJ
= 360° - 152° - 132°
= 76° (Angles at a point)
(b)
∠NMH
= 180° - 152°
= 28°(Angles on a straight line)
∠LKM
= ∠KMN
= 28° + 20°
= 48° (Alternate angles)
Answer(s): (a) 76°; (b) 48°