PSLEIn the figure, BCDE is a parallelogram. BZE and ZDA are straight lines. ∠ADE = 150°, ∠BED = 45° and ∠BDZ = 21°.
- Find ∠CDA.
- Find ∠CBD.
(a)
∠CDE
= 180° - 45°
= 135° (Interior angles)
∠CDA
= 360° - 150° - 135°
= 75° (Angles at a point)
(b)
∠EDZ
= 180° - 150°
= 30°(Angles on a straight line)
∠CBD
= ∠BDE
= 30° + 21°
= 51° (Alternate angles)
Answer(s): (a) 75°; (b) 51°