PSLEIn the figure, KLMN is a parallelogram. KHN and HMJ are straight lines. ∠JMN = 151°, ∠KNM = 42° and ∠KMH = 22°.
- Find ∠LMJ.
- Find ∠LKM.
(a)
∠LMN
= 180° - 42°
= 138° (Interior angles)
∠LMJ
= 360° - 151° - 138°
= 71° (Angles at a point)
(b)
∠NMH
= 180° - 151°
= 29°(Angles on a straight line)
∠LKM
= ∠KMN
= 29° + 22°
= 51° (Alternate angles)
Answer(s): (a) 71°; (b) 51°