PSLEIn the figure, FGHJ is a parallelogram. FDJ and DHE are straight lines. ∠EHJ = 153°, ∠FJH = 44° and ∠FHD = 20°.
- Find ∠GHE.
- Find ∠GFH.
(a)
∠GHJ
= 180° - 44°
= 136° (Interior angles)
∠GHE
= 360° - 153° - 136°
= 71° (Angles at a point)
(b)
∠JHD
= 180° - 153°
= 27°(Angles on a straight line)
∠GFH
= ∠FHJ
= 27° + 20°
= 47° (Alternate angles)
Answer(s): (a) 71°; (b) 47°