PSLEIn the figure, HJKL is a parallelogram. HFL and FKG are straight lines. ∠GKL = 151°, ∠HLK = 43° and ∠HKF = 17°.
- Find ∠JKG.
- Find ∠JHK.
(a)
∠JKL
= 180° - 43°
= 137° (Interior angles)
∠JKG
= 360° - 151° - 137°
= 72° (Angles at a point)
(b)
∠LKF
= 180° - 151°
= 29°(Angles on a straight line)
∠JHK
= ∠HKL
= 29° + 17°
= 46° (Alternate angles)
Answer(s): (a) 72°; (b) 46°