PSLEIn the figure, JKLM is a parallelogram. JGM and GLH are straight lines. ∠HLM = 152°, ∠JML = 45° and ∠JLG = 22°.
- Find ∠KLH.
- Find ∠KJL.
(a)
∠KLM
= 180° - 45°
= 135° (Interior angles)
∠KLH
= 360° - 152° - 135°
= 73° (Angles at a point)
(b)
∠MLG
= 180° - 152°
= 28°(Angles on a straight line)
∠KJL
= ∠JLM
= 28° + 22°
= 50° (Alternate angles)
Answer(s): (a) 73°; (b) 50°