PSLEIn the figure, CDEF is a parallelogram. CAF and AEB are straight lines. ∠BEF = 152°, ∠CFE = 46° and ∠CEA = 19°.
- Find ∠DEB.
- Find ∠DCE.
(a)
∠DEF
= 180° - 46°
= 134° (Interior angles)
∠DEB
= 360° - 152° - 134°
= 74° (Angles at a point)
(b)
∠FEA
= 180° - 152°
= 28°(Angles on a straight line)
∠DCE
= ∠CEF
= 28° + 19°
= 47° (Alternate angles)
Answer(s): (a) 74°; (b) 47°