PSLEIn the figure, EFGH is a parallelogram. ECH and CGD are straight lines. ∠DGH = 148°, ∠EHG = 43° and ∠EGC = 20°.
- Find ∠FGD.
- Find ∠FEG.
(a)
∠FGH
= 180° - 43°
= 137° (Interior angles)
∠FGD
= 360° - 148° - 137°
= 75° (Angles at a point)
(b)
∠HGC
= 180° - 148°
= 32°(Angles on a straight line)
∠FEG
= ∠EGH
= 32° + 20°
= 52° (Alternate angles)
Answer(s): (a) 75°; (b) 52°