PSLEIn the figure, HJKL is a parallelogram. HFL and FKG are straight lines. ∠GKL = 151°, ∠HLK = 44° and ∠HKF = 22°.
- Find ∠JKG.
- Find ∠JHK.
(a)
∠JKL
= 180° - 44°
= 136° (Interior angles)
∠JKG
= 360° - 151° - 136°
= 73° (Angles at a point)
(b)
∠LKF
= 180° - 151°
= 29°(Angles on a straight line)
∠JHK
= ∠HKL
= 29° + 22°
= 51° (Alternate angles)
Answer(s): (a) 73°; (b) 51°