PSLEIn the figure, BCDE is a parallelogram. BZE and ZDA are straight lines. ∠ADE = 150°, ∠BED = 48° and ∠BDZ = 20°.
- Find ∠CDA.
- Find ∠CBD.
(a)
∠CDE
= 180° - 48°
= 132° (Interior angles)
∠CDA
= 360° - 150° - 132°
= 78° (Angles at a point)
(b)
∠EDZ
= 180° - 150°
= 30°(Angles on a straight line)
∠CBD
= ∠BDE
= 30° + 20°
= 50° (Alternate angles)
Answer(s): (a) 78°; (b) 50°