PSLEIn the figure, HJKL is a parallelogram. HFL and FKG are straight lines. ∠GKL = 149°, ∠HLK = 44° and ∠HKF = 22°.
- Find ∠JKG.
- Find ∠JHK.
(a)
∠JKL
= 180° - 44°
= 136° (Interior angles)
∠JKG
= 360° - 149° - 136°
= 75° (Angles at a point)
(b)
∠LKF
= 180° - 149°
= 31°(Angles on a straight line)
∠JHK
= ∠HKL
= 31° + 22°
= 53° (Alternate angles)
Answer(s): (a) 75°; (b) 53°