PSLEIn the figure, ZABC is a parallelogram. ZXC and XBY are straight lines. ∠YBC = 152°, ∠ZCB = 46° and ∠ZBX = 22°.
- Find ∠ABY.
- Find ∠AZB.
(a)
∠ABC
= 180° - 46°
= 134° (Interior angles)
∠ABY
= 360° - 152° - 134°
= 74° (Angles at a point)
(b)
∠CBX
= 180° - 152°
= 28°(Angles on a straight line)
∠AZB
= ∠ZBC
= 28° + 22°
= 50° (Alternate angles)
Answer(s): (a) 74°; (b) 50°