PSLEIn the figure, DEFG is a parallelogram. DBG and BFC are straight lines. ∠CFG = 149°, ∠DGF = 42° and ∠DFB = 18°.
- Find ∠EFC.
- Find ∠EDF.
(a)
∠EFG
= 180° - 42°
= 138° (Interior angles)
∠EFC
= 360° - 149° - 138°
= 73° (Angles at a point)
(b)
∠GFB
= 180° - 149°
= 31°(Angles on a straight line)
∠EDF
= ∠DFG
= 31° + 18°
= 49° (Alternate angles)
Answer(s): (a) 73°; (b) 49°