PSLEIn the figure, DEFG is a parallelogram. DBG and BFC are straight lines. ∠CFG = 151°, ∠DGF = 46° and ∠DFB = 17°.
- Find ∠EFC.
- Find ∠EDF.
(a)
∠EFG
= 180° - 46°
= 134° (Interior angles)
∠EFC
= 360° - 151° - 134°
= 75° (Angles at a point)
(b)
∠GFB
= 180° - 151°
= 29°(Angles on a straight line)
∠EDF
= ∠DFG
= 29° + 17°
= 46° (Alternate angles)
Answer(s): (a) 75°; (b) 46°