PSLEIn the figure, EFGH is a parallelogram. ECH and CGD are straight lines. ∠DGH = 152°, ∠EHG = 44° and ∠EGC = 20°.
- Find ∠FGD.
- Find ∠FEG.
(a)
∠FGH
= 180° - 44°
= 136° (Interior angles)
∠FGD
= 360° - 152° - 136°
= 72° (Angles at a point)
(b)
∠HGC
= 180° - 152°
= 28°(Angles on a straight line)
∠FEG
= ∠EGH
= 28° + 20°
= 48° (Alternate angles)
Answer(s): (a) 72°; (b) 48°