PSLEIn the figure, ABCD is a parallelogram. AYD and YCZ are straight lines. ∠ZCD = 150°, ∠ADC = 47° and ∠ACY = 22°.
- Find ∠BCZ.
- Find ∠BAC.
(a)
∠BCD
= 180° - 47°
= 133° (Interior angles)
∠BCZ
= 360° - 150° - 133°
= 77° (Angles at a point)
(b)
∠DCY
= 180° - 150°
= 30°(Angles on a straight line)
∠BAC
= ∠ACD
= 30° + 22°
= 52° (Alternate angles)
Answer(s): (a) 77°; (b) 52°