PSLEIn the figure, DEFG is a parallelogram. DBG and BFC are straight lines. ∠CFG = 148°, ∠DGF = 48° and ∠DFB = 19°.
- Find ∠EFC.
- Find ∠EDF.
(a)
∠EFG
= 180° - 48°
= 132° (Interior angles)
∠EFC
= 360° - 148° - 132°
= 80° (Angles at a point)
(b)
∠GFB
= 180° - 148°
= 32°(Angles on a straight line)
∠EDF
= ∠DFG
= 32° + 19°
= 51° (Alternate angles)
Answer(s): (a) 80°; (b) 51°