In the figure, XYZA is a parallelogram with the length of XA 2 times the length of XY. XAB is an equilateral triangle. C is a point on XB such that XC = CB. ∠YZA is 108°. Find ∠CYZ .
4 m
In the figure, XYZA is a parallelogram with the length of XA 2 times the length of XY. XAB is an equilateral triangle. C is a point on XB such that XC = CB. ∠YZA is 108°. Find ∠CYZ .
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Ischool Pte Ltd
Date:18 May 2024
Topic:
ANGLES
Question Code:
P6.AN.NK.17051716
Student:
Class:
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In the figure, XYZA is a parallelogram with the length of XA 2 times the length of XY. XAB is an equilateral triangle. C is a point on XB such that XC = CB. ∠YZA is 108°. Find ∠CYZ .
(4 m)
Ischool Pte Ltd
Date:
18 May 2024
Topic:
ANGLES
Question Code:
P6.AN.NK.17051716
Student:
Class:
Level:
School:
In the figure, XYZA is a parallelogram with the length of XA 2 times the length of XY. XAB is an equilateral triangle. C is a point on XB such that XC = CB. ∠YZA is 108°. Find ∠CYZ .
In the figure, XYZA is a parallelogram with the length of XA 2 times the length of XY. XAB is an equilateral triangle. C is a point on XB such that XC = CB. ∠YZA is 108°. Find ∠CYZ .
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ISchool Pte Ltd
Date:18 May 2024
Topic:ANGLES
Question Number:P6.AN.NK.17051716-A1
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