In the figure, CDEF is a parallelogram with the length of CF 2 times the length of CD. CFG is an equilateral triangle. H is a point on CG such that CH = HG. ∠DEF is 106°. Find ∠HDE .
4 m
In the figure, CDEF is a parallelogram with the length of CF 2 times the length of CD. CFG is an equilateral triangle. H is a point on CG such that CH = HG. ∠DEF is 106°. Find ∠HDE .
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Ischool Pte Ltd
Date:16 May 2024
Topic:
ANGLES
Question Code:
P6.AN.NK.17051716
Student:
Class:
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In the figure, CDEF is a parallelogram with the length of CF 2 times the length of CD. CFG is an equilateral triangle. H is a point on CG such that CH = HG. ∠DEF is 106°. Find ∠HDE .
(4 m)
Ischool Pte Ltd
Date:
16 May 2024
Topic:
ANGLES
Question Code:
P6.AN.NK.17051716
Student:
Class:
Level:
School:
In the figure, CDEF is a parallelogram with the length of CF 2 times the length of CD. CFG is an equilateral triangle. H is a point on CG such that CH = HG. ∠DEF is 106°. Find ∠HDE .
In the figure, CDEF is a parallelogram with the length of CF 2 times the length of CD. CFG is an equilateral triangle. H is a point on CG such that CH = HG. ∠DEF is 106°. Find ∠HDE .
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ISchool Pte Ltd
Date:16 May 2024
Topic:ANGLES
Question Number:P6.AN.NK.17051716-A1
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