In the figure, PQRS is a parallelogram with the length of PS 2 times the length of PQ. PST is an equilateral triangle. U is a point on PT such that PU = UT. ∠QRS is 106°. Find ∠UQR .
4 m
In the figure, PQRS is a parallelogram with the length of PS 2 times the length of PQ. PST is an equilateral triangle. U is a point on PT such that PU = UT. ∠QRS is 106°. Find ∠UQR .
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Ischool Pte Ltd
Date:18 May 2024
Topic:
ANGLES
Question Code:
P6.AN.NK.17051716
Student:
Class:
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In the figure, PQRS is a parallelogram with the length of PS 2 times the length of PQ. PST is an equilateral triangle. U is a point on PT such that PU = UT. ∠QRS is 106°. Find ∠UQR .
(4 m)
Ischool Pte Ltd
Date:
18 May 2024
Topic:
ANGLES
Question Code:
P6.AN.NK.17051716
Student:
Class:
Level:
School:
In the figure, PQRS is a parallelogram with the length of PS 2 times the length of PQ. PST is an equilateral triangle. U is a point on PT such that PU = UT. ∠QRS is 106°. Find ∠UQR .
In the figure, PQRS is a parallelogram with the length of PS 2 times the length of PQ. PST is an equilateral triangle. U is a point on PT such that PU = UT. ∠QRS is 106°. Find ∠UQR .
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ISchool Pte Ltd
Date:18 May 2024
Topic:ANGLES
Question Number:P6.AN.NK.17051716-A1
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