In the figure, ABCD is a parallelogram with the length of AD 2 times the length of AB. ADE is an equilateral triangle. F is a point on AE such that AF = FE. ∠BCD is 108°. Find ∠FBC .
4 m
In the figure, ABCD is a parallelogram with the length of AD 2 times the length of AB. ADE is an equilateral triangle. F is a point on AE such that AF = FE. ∠BCD is 108°. Find ∠FBC .
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Ischool Pte Ltd
Date:16 Jun 2024
Topic:
ANGLES
Question Code:
P6.AN.NK.17051716
Student:
Class:
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In the figure, ABCD is a parallelogram with the length of AD 2 times the length of AB. ADE is an equilateral triangle. F is a point on AE such that AF = FE. ∠BCD is 108°. Find ∠FBC .
(4 m)
Ischool Pte Ltd
Date:
16 Jun 2024
Topic:
ANGLES
Question Code:
P6.AN.NK.17051716
Student:
Class:
Level:
School:
In the figure, ABCD is a parallelogram with the length of AD 2 times the length of AB. ADE is an equilateral triangle. F is a point on AE such that AF = FE. ∠BCD is 108°. Find ∠FBC .
In the figure, ABCD is a parallelogram with the length of AD 2 times the length of AB. ADE is an equilateral triangle. F is a point on AE such that AF = FE. ∠BCD is 108°. Find ∠FBC .
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ISchool Pte Ltd
Date:16 Jun 2024
Topic:ANGLES
Question Number:P6.AN.NK.17051716-A1
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