In the figure, YZAB is a parallelogram with the length of YB 2 times the length of YZ. YBC is an equilateral triangle. D is a point on YC such that YD = DC. ∠ZAB is 110°. Find ∠DZA .
4 m
In the figure, YZAB is a parallelogram with the length of YB 2 times the length of YZ. YBC is an equilateral triangle. D is a point on YC such that YD = DC. ∠ZAB is 110°. Find ∠DZA .
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Ischool Pte Ltd
Date:01 Jun 2024
Topic:
ANGLES
Question Code:
P6.AN.NK.17051716
Student:
Class:
Level:
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In the figure, YZAB is a parallelogram with the length of YB 2 times the length of YZ. YBC is an equilateral triangle. D is a point on YC such that YD = DC. ∠ZAB is 110°. Find ∠DZA .
(4 m)
Ischool Pte Ltd
Date:
01 Jun 2024
Topic:
ANGLES
Question Code:
P6.AN.NK.17051716
Student:
Class:
Level:
School:
In the figure, YZAB is a parallelogram with the length of YB 2 times the length of YZ. YBC is an equilateral triangle. D is a point on YC such that YD = DC. ∠ZAB is 110°. Find ∠DZA .
In the figure, YZAB is a parallelogram with the length of YB 2 times the length of YZ. YBC is an equilateral triangle. D is a point on YC such that YD = DC. ∠ZAB is 110°. Find ∠DZA .
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ISchool Pte Ltd
Date:01 Jun 2024
Topic:ANGLES
Question Number:P6.AN.NK.17051716-A1
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