In the figure, HJKL is a parallelogram with the length of HL 2 times the length of HJ. HLM is an equilateral triangle. N is a point on HM such that HN = NM. ∠JKL is 104°. Find ∠NJK .
4 m
In the figure, HJKL is a parallelogram with the length of HL 2 times the length of HJ. HLM is an equilateral triangle. N is a point on HM such that HN = NM. ∠JKL is 104°. Find ∠NJK .
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Ischool Pte Ltd
Date:08 May 2024
Topic:
ANGLES
Question Code:
P6.AN.NK.17051716
Student:
Class:
Level:
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In the figure, HJKL is a parallelogram with the length of HL 2 times the length of HJ. HLM is an equilateral triangle. N is a point on HM such that HN = NM. ∠JKL is 104°. Find ∠NJK .
(4 m)
Ischool Pte Ltd
Date:
08 May 2024
Topic:
ANGLES
Question Code:
P6.AN.NK.17051716
Student:
Class:
Level:
School:
In the figure, HJKL is a parallelogram with the length of HL 2 times the length of HJ. HLM is an equilateral triangle. N is a point on HM such that HN = NM. ∠JKL is 104°. Find ∠NJK .
In the figure, HJKL is a parallelogram with the length of HL 2 times the length of HJ. HLM is an equilateral triangle. N is a point on HM such that HN = NM. ∠JKL is 104°. Find ∠NJK .
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ISchool Pte Ltd
Date:08 May 2024
Topic:ANGLES
Question Number:P6.AN.NK.17051716-A1
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