In the figure, CDEF is a parallelogram. EH, HJ and CD are straight lines. CFG is an isosceles triangle.
- Find ∠n.
- Find ∠p.
(a)
∠EHC = ∠DCJ = 66° (Corresponding angles, CD//HE)
∠HGC
= 180° - ∠EHC - ∠HCG
= 180° - 66° - 19°
= 95° (Angles sum of triangle)
∠FGC
= 180° - 95°
= 85° (Angles on a straight line)
∠GFC = ∠FGC = 85° (Isosceles triangle)
∠n
= ∠GFC
= 85° (Corresponding angles, DE//CF)
(b)
∠p
= 180° - 85° - 85°
= 10° (Isosceles triangle CFG)
Answer(s): (a) 85°; (b) 10°
