In the figure, HJKL is a parallelogram. KN, NP and HJ are straight lines. HLM is an isosceles triangle.
- Find ∠v.
- Find ∠w.
(a)
∠KNH = ∠JHP = 65° (Corresponding angles, HJ//NK)
∠NMH
= 180° - ∠KNH - ∠NHM
= 180° - 65° - 17°
= 98° (Angles sum of triangle)
∠LMH
= 180° - 98°
= 82° (Angles on a straight line)
∠MLH = ∠LMH = 82° (Isosceles triangle)
∠v
= ∠MLH
= 82° (Corresponding angles, JK//HL)
(b)
∠w
= 180° - 82° - 82°
= 16° (Isosceles triangle HLM)
Answer(s): (a) 82°; (b) 16°