In the figure, DEFG is a parallelogram. FJ, JK and DE are straight lines. DGH is an isosceles triangle.
- Find ∠w.
- Find ∠x.
(a)
∠FJD = ∠EDK = 65° (Corresponding angles, DE//JF)
∠JHD
= 180° - ∠FJD - ∠JDH
= 180° - 65° - 20°
= 95° (Angles sum of triangle)
∠GHD
= 180° - 95°
= 85° (Angles on a straight line)
∠HGD = ∠GHD = 85° (Isosceles triangle)
∠w
= ∠HGD
= 85° (Corresponding angles, EF//DG)
(b)
∠x
= 180° - 85° - 85°
= 10° (Isosceles triangle DGH)
Answer(s): (a) 85°; (b) 10°
