In the figure, BCDE is a parallelogram. DG, GH and BC are straight lines. BEF is an isosceles triangle.
- Find ∠v.
- Find ∠w.
(a)
∠DGB = ∠CBH = 64° (Corresponding angles, BC//GD)
∠GFB
= 180° - ∠DGB - ∠GBF
= 180° - 64° - 19°
= 97° (Angles sum of triangle)
∠EFB
= 180° - 97°
= 83° (Angles on a straight line)
∠FEB = ∠EFB = 83° (Isosceles triangle)
∠v
= ∠FEB
= 83° (Corresponding angles, CD//BE)
(b)
∠w
= 180° - 83° - 83°
= 14° (Isosceles triangle BEF)
Answer(s): (a) 83°; (b) 14°