In the figure, FGHJ is a parallelogram. HL, LM and FG are straight lines. FJK is an isosceles triangle.
- Find ∠n.
- Find ∠p.
(a)
∠HLF = ∠GFM = 61° (Corresponding angles, FG//LH)
∠LKF
= 180° - ∠HLF - ∠LFK
= 180° - 61° - 15°
= 104° (Angles sum of triangle)
∠JKF
= 180° - 104°
= 76° (Angles on a straight line)
∠KJF = ∠JKF = 76° (Isosceles triangle)
∠n
= ∠KJF
= 76° (Corresponding angles, GH//FJ)
(b)
∠p
= 180° - 76° - 76°
= 28° (Isosceles triangle FJK)
Answer(s): (a) 76°; (b) 28°