In the figure, YZAB is a parallelogram. AD, DE and YZ are straight lines. YBC is an isosceles triangle.
- Find ∠h.
- Find ∠i.
(a)
∠ADY = ∠ZYE = 58° (Corresponding angles, YZ//DA)
∠DCY
= 180° - ∠ADY - ∠DYC
= 180° - 58° - 18°
= 104° (Angles sum of triangle)
∠BCY
= 180° - 104°
= 76° (Angles on a straight line)
∠CBY = ∠BCY = 76° (Isosceles triangle)
∠h
= ∠CBY
= 76° (Corresponding angles, ZA//YB)
(b)
∠i
= 180° - 76° - 76°
= 28° (Isosceles triangle YBC)
Answer(s): (a) 76°; (b) 28°