In the figure, ABCD is a parallelogram. CF, FG and AB are straight lines. ADE is an isosceles triangle.
- Find ∠f.
- Find ∠g.
(a)
∠CFA = ∠BAG = 58° (Corresponding angles, AB//FC)
∠FEA
= 180° - ∠CFA - ∠FAE
= 180° - 58° - 15°
= 107° (Angles sum of triangle)
∠DEA
= 180° - 107°
= 73° (Angles on a straight line)
∠EDA = ∠DEA = 73° (Isosceles triangle)
∠f
= ∠EDA
= 73° (Corresponding angles, BC//AD)
(b)
∠g
= 180° - 73° - 73°
= 34° (Isosceles triangle ADE)
Answer(s): (a) 73°; (b) 34°