In the figure, ABCD is a parallelogram. CF, FG and AB are straight lines. ADE is an isosceles triangle.
- Find ∠n.
- Find ∠p.
(a)
∠CFA = ∠BAG = 58° (Corresponding angles, AB//FC)
∠FEA
= 180° - ∠CFA - ∠FAE
= 180° - 58° - 19°
= 103° (Angles sum of triangle)
∠DEA
= 180° - 103°
= 77° (Angles on a straight line)
∠EDA = ∠DEA = 77° (Isosceles triangle)
∠n
= ∠EDA
= 77° (Corresponding angles, BC//AD)
(b)
∠p
= 180° - 77° - 77°
= 26° (Isosceles triangle ADE)
Answer(s): (a) 77°; (b) 26°