In the figure, ZABC is a parallelogram. BE, EF and ZA are straight lines. ZCD is an isosceles triangle.
- Find ∠d.
- Find ∠e.
(a)
∠BEZ = ∠AZF = 58° (Corresponding angles, ZA//EB)
∠EDZ
= 180° - ∠BEZ - ∠EZD
= 180° - 58° - 21°
= 101° (Angles sum of triangle)
∠CDZ
= 180° - 101°
= 79° (Angles on a straight line)
∠DCZ = ∠CDZ = 79° (Isosceles triangle)
∠d
= ∠DCZ
= 79° (Corresponding angles, AB//ZC)
(b)
∠e
= 180° - 79° - 79°
= 22° (Isosceles triangle ZCD)
Answer(s): (a) 79°; (b) 22°