In the figure, ABCD is a parallelogram. CF, FG and AB are straight lines. ADE is an isosceles triangle.
- Find ∠k.
- Find ∠m.
(a)
∠CFA = ∠BAG = 66° (Corresponding angles, AB//FC)
∠FEA
= 180° - ∠CFA - ∠FAE
= 180° - 66° - 18°
= 96° (Angles sum of triangle)
∠DEA
= 180° - 96°
= 84° (Angles on a straight line)
∠EDA = ∠DEA = 84° (Isosceles triangle)
∠k
= ∠EDA
= 84° (Corresponding angles, BC//AD)
(b)
∠m
= 180° - 84° - 84°
= 12° (Isosceles triangle ADE)
Answer(s): (a) 84°; (b) 12°