In the figure, ABCD is a parallelogram. CF, FG and AB are straight lines. ADE is an isosceles triangle.
- Find ∠t.
- Find ∠v.
(a)
∠CFA = ∠BAG = 64° (Corresponding angles, AB//FC)
∠FEA
= 180° - ∠CFA - ∠FAE
= 180° - 64° - 19°
= 97° (Angles sum of triangle)
∠DEA
= 180° - 97°
= 83° (Angles on a straight line)
∠EDA = ∠DEA = 83° (Isosceles triangle)
∠t
= ∠EDA
= 83° (Corresponding angles, BC//AD)
(b)
∠v
= 180° - 83° - 83°
= 14° (Isosceles triangle ADE)
Answer(s): (a) 83°; (b) 14°