In the figure, HJKL is a parallelogram. KN, NP and HJ are straight lines. HLM is an isosceles triangle.
- Find ∠r.
- Find ∠s.
(a)
∠KNH = ∠JHP = 58° (Corresponding angles, HJ//NK)
∠NMH
= 180° - ∠KNH - ∠NHM
= 180° - 58° - 18°
= 104° (Angles sum of triangle)
∠LMH
= 180° - 104°
= 76° (Angles on a straight line)
∠MLH = ∠LMH = 76° (Isosceles triangle)
∠r
= ∠MLH
= 76° (Corresponding angles, JK//HL)
(b)
∠s
= 180° - 76° - 76°
= 28° (Isosceles triangle HLM)
Answer(s): (a) 76°; (b) 28°