In the figure, ABCD is a parallelogram. CF, FG and AB are straight lines. ADE is an isosceles triangle.
- Find ∠x.
- Find ∠y.
(a)
∠CFA = ∠BAG = 64° (Corresponding angles, AB//FC)
∠FEA
= 180° - ∠CFA - ∠FAE
= 180° - 64° - 17°
= 99° (Angles sum of triangle)
∠DEA
= 180° - 99°
= 81° (Angles on a straight line)
∠EDA = ∠DEA = 81° (Isosceles triangle)
∠x
= ∠EDA
= 81° (Corresponding angles, BC//AD)
(b)
∠y
= 180° - 81° - 81°
= 18° (Isosceles triangle ADE)
Answer(s): (a) 81°; (b) 18°