In the figure, CDEF is a parallelogram. EH, HJ and CD are straight lines. CFG is an isosceles triangle.
- Find ∠t.
- Find ∠v.
(a)
∠EHC = ∠DCJ = 60° (Corresponding angles, CD//HE)
∠HGC
= 180° - ∠EHC - ∠HCG
= 180° - 60° - 16°
= 104° (Angles sum of triangle)
∠FGC
= 180° - 104°
= 76° (Angles on a straight line)
∠GFC = ∠FGC = 76° (Isosceles triangle)
∠t
= ∠GFC
= 76° (Corresponding angles, DE//CF)
(b)
∠v
= 180° - 76° - 76°
= 28° (Isosceles triangle CFG)
Answer(s): (a) 76°; (b) 28°