In the figure, EFGH is a parallelogram. GK, KL and EF are straight lines. EHJ is an isosceles triangle.
- Find ∠w.
- Find ∠x.
(a)
∠GKE = ∠FEL = 62° (Corresponding angles, EF//KG)
∠KJE
= 180° - ∠GKE - ∠KEJ
= 180° - 62° - 15°
= 103° (Angles sum of triangle)
∠HJE
= 180° - 103°
= 77° (Angles on a straight line)
∠JHE = ∠HJE = 77° (Isosceles triangle)
∠w
= ∠JHE
= 77° (Corresponding angles, FG//EH)
(b)
∠x
= 180° - 77° - 77°
= 26° (Isosceles triangle EHJ)
Answer(s): (a) 77°; (b) 26°