In the figure, HJKL is a parallelogram. KN, NP and HJ are straight lines. HLM is an isosceles triangle.
- Find ∠i.
- Find ∠j.
(a)
∠KNH = ∠JHP = 65° (Corresponding angles, HJ//NK)
∠NMH
= 180° - ∠KNH - ∠NHM
= 180° - 65° - 16°
= 99° (Angles sum of triangle)
∠LMH
= 180° - 99°
= 81° (Angles on a straight line)
∠MLH = ∠LMH = 81° (Isosceles triangle)
∠i
= ∠MLH
= 81° (Corresponding angles, JK//HL)
(b)
∠j
= 180° - 81° - 81°
= 18° (Isosceles triangle HLM)
Answer(s): (a) 81°; (b) 18°