In the figure, ABCD is a parallelogram. CF, FG and AB are straight lines. ADE is an isosceles triangle.
- Find ∠e.
- Find ∠f.
(a)
∠CFA = ∠BAG = 63° (Corresponding angles, AB//FC)
∠FEA
= 180° - ∠CFA - ∠FAE
= 180° - 63° - 19°
= 98° (Angles sum of triangle)
∠DEA
= 180° - 98°
= 82° (Angles on a straight line)
∠EDA = ∠DEA = 82° (Isosceles triangle)
∠e
= ∠EDA
= 82° (Corresponding angles, BC//AD)
(b)
∠f
= 180° - 82° - 82°
= 16° (Isosceles triangle ADE)
Answer(s): (a) 82°; (b) 16°