In the figure, CDEF is a parallelogram. EH, HJ and CD are straight lines. CFG is an isosceles triangle.
- Find ∠e.
- Find ∠f.
(a)
∠EHC = ∠DCJ = 63° (Corresponding angles, CD//HE)
∠HGC
= 180° - ∠EHC - ∠HCG
= 180° - 63° - 20°
= 97° (Angles sum of triangle)
∠FGC
= 180° - 97°
= 83° (Angles on a straight line)
∠GFC = ∠FGC = 83° (Isosceles triangle)
∠e
= ∠GFC
= 83° (Corresponding angles, DE//CF)
(b)
∠f
= 180° - 83° - 83°
= 14° (Isosceles triangle CFG)
Answer(s): (a) 83°; (b) 14°